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12y^2-24y-36=0
a = 12; b = -24; c = -36;
Δ = b2-4ac
Δ = -242-4·12·(-36)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-48}{2*12}=\frac{-24}{24} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+48}{2*12}=\frac{72}{24} =3 $
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